A particular city had a population of 27 comma 000 in 1910 and a population of 30 comma 000 in 1940. Assuming that its population continues to grow exponentially at a constant rate, what population will it have in 2000?

Population of 36,997 in 2000.

Step-by-step explanation:

The exponential equation for population growth is:

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

A particular city had a population of 27 comma 000 in 1910 and a population of 30 comma 000 in 1940.

This means that

1940 is 30 years after 1910, since 1940-1910 = 30.

So

Replacing this in the equation, we can find the growth rate.

Applying ln to both sides

So

Assuming that its population continues to grow exponentially at a constant rate, what population will it have in 2000?

20000 is 90 years after 1910, so this is P(90).

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following