A person is taking a 77-question multiple-choice test for which each question has three answer choices, only one of which is correct. The person decides on answers by rolling a fair die and marking the first answer choice if the die shows 1 or 2, the second if it shows 3 or 4, and the third if it shows 5 or 6. Find the probability that the person gets fewer than 33 correct answersanswers?

0.9488

Step-by-step explanation:

We have a binomial experiment with n = 77 independent trials, in each trial, we can have a success or a fail, the probability of success is p = 1/3 (q = 2/3) because each question has three answer choices and only one is correct, besides the person decides on answers by rolling a fair die. Therefore, the probability that the person gets exactly x correct answers is given by  

and the probability that the person gets fewer than 33 correct answers is given by = 0.9488

i'm not sure i quite understand, could you provide more information?

7

step-by-step explanation: