What is the equation in point slope form of the line that passes through the point
(2, 6) and has a slope of 5?
oy- 6 = 5 (x - 2)
o y - 2 = 5(x – 6)
oy+6 = 5 (x + 2)
o y + 2 = 5 (x + 6)

Point-slope form:  y - y₁ = m(x - x₁)

[m is the slope, x₁ and y₁ ---> (x₁, y₁) is the point]

Since you know:

m = 5

(2, 6) = (x₁, y₁)       Substitute/plug in the values into the equation

y - y₁ = m(x - x₁)

y - 6 = 5(x - 2)   The 1st option is your answer

7

step-by-step explanation:

it would be 6xy and -16xy.