A rectangular photo has a frame that is 1 inch wide. If the photo is twice as long as it is wide and the area of the photo and frame together is 60 inches, what are the dimensions of the photo?

the length is 8 inches

The with is 4 inches

Step-by-step explanation:

Let L represent the length of the photo.

Let W represent the width of the photo.

If the photo is twice as long as it is wide, it means that

L = 2W

The rectangular photo has a frame that is 1 inch wide. This means that

The length of the photo and the frame is L + 2

The width of the photo and the frame is W + 2

If the area of the photo and frame together is 60 inches², it means that

(L + 2)(W + 2) = 60 - - - - - - - - - - -1

Substituting L = 2W into equation 1, it becomes

(2W + 2)(W + 2) = 60

2W² + 4W + 2W + 4 = 60

2W² + 6W + 4 - 60 = 0

2W² + 6W - 56 = 0

Dividing through by 2, it becomes

W² + 3W - 28 = 0

W² + 7W - 4W - 28 = 0

W(W + 7) - 4(W + 7) = 0

(W - 4)(W + 7) = 0

W = 4 or W = - 7

The width cannot be negative , therefore, W = 4

Substituting W = 4 into L = 2W, ut becomes

L = 2 × 4 = 8 inches

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

rick would give her the best deal as he will charge $8.88 per hour