Please help me with this problem

Work Shown:

The rule is to start with the first term (a1 = 3), then double that and subtract off 1 to get the next term.

Keep doing the "double the value and subtract 1" process to generate as many terms as you want.

a1 = first term = 3

a2 = second term

a2 = 2*a1 - 1   double the previous term, subtract 1

a2 = 2*3 - 1

a2 = 6 - 1

a2 = 5

The second term is 5

a3 = third term

a3 = 2*a2 - 1

a3 = 2*5 - 1

a3 = 10 - 1

a3 = 9

The third term is 9

a4 = fourth term

a4 = 2*a3 - 1

a4 = 2*9 - 1

a4 = 18 - 1

a4 = 17

The fourth term is 17

The first four terms of this recursive sequence is: 3, 5, 9, 17

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

step-by-step explanation:

my butt