Prove the divisibility of the following numbers: 45^10·5^40 by 25^20

For this case we have the following expressions:

and

Let:

(Integer m)

(Integer n)

By definition, an integer m is divisible by an integer n if the remainder of the division is 0. That is, there is an integer p such that:

Rewriting the expression we have:

So:

We cancel similar terms:

We check:

If they are divisible

5

step-by-step explanation: