A certain shop repairs both audio and video components. Let A denote the event that the next component brought in for repair is an audio component, and let B be the event that the next component is a compact disc player (so the event B is contained in A). Suppose that P(A) 1?4 .6 and P(B) 1?4 .05. What is P(B | A)?

The correct answer is, P (B | A) = 0.0833.

Step-by-step explanation:

It is provided that:

A = the event that the next component brought in for repair is an audio component.

B = the event that the next component is a compact disc player

The event B is contained in A. This implies that P (B) = P (A and B) .

P (A) = 0.60 and P (B) = P (A and B) = 0.05.

According to the conditional probability rule:

Determine the probability of the event (B | A) is:

Thus, the probability of event B given event A is 0.0833.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

i belive those are the ones that are under 90 degreese.