One hundred forty-one of the 224 high school students surveyed at a local school say they plan on taking some form of postsecondary education. Calculate the margin of error (ME), rounded to the nearest tenth of a percent. Is it reasonable that the state education department claims the percentage for the entire state is 68%

Margin error (ME) = 5%

It's quite reasonable

Step-by-step explanation:

Since total of students are 224 and 141 wants to further on post secondary school

Therefore, percentage that wants to further = 141/224×100%

= 62.9%

Approximately 63%

Margin error = 68% - 63%

= 5%

This implies that the error is 5% from what the state department stated, which is quite reasonable.

24

step-by-step explanation:

24/56=hx^7

step-by-step explanation: