The length of a rectangle is 5cm more than it's width. If the width is increased by 2 cm and the length is increased by 3 cm a new rectangle is formed that has an area of 46 cm squared more than the original rectangle. Find dimensions of the original rectangle.

The dimensions of the original rectangle are:

Length 11 cm

Width 6 cm

Step-by-step explanation:

Let

x ----> the original length

y ----> the original width

we know that

The original area is

----> equation A

----> equation B

The new area is

----> equation C

----> equation D

substitute equation A and equation C in equation D

----> equation E

substitute equation B in equation E

solve for y

(

Find the value of x

therefore

The dimensions of the original rectangle are:

Length 11 cm

Width 6 cm

18.8 cubic inches.

step-by-step explanation:

volume of a cone = πr²h

r = 1.5 inches

h = 8 inches

pi = 3.14

volume of our cone = × 3.14 × 1.5² × 8 = 18.84 square inches

or equals to 18.8 square inches rounded up to nearest tenth.