Trapezoid jklm is shown on the coordinate plane below:
trapezoid jklm on the coordinate plane with ordered pairs at j negative 6, 5, at k negative 3, 5, at l negative 1, 2, at m negative 8, 2.
if trapezoid jklm is translated according to the rule (x, y) → (x + 2, y − 6), what are the coordinates of point l'?

The Coordinate of point L' is (1,-4)

Step-by-step explanation:

Trapezoid JKLM on the coordinate plane with ordered pairs

J(-6,5)

K(-3,5)

L(-1,2)

M(-8,2)

If trapezoid JKLM is translated according to the rule (x, y) → (x + 2, y − 6)

We need to find the coordinate of L'

L(-1,2)

(x, y) → (x + 2, y − 6)

Rule of translation: x-coordinate shift 2 unit right and y-coordinate shift 6 unit down.

    L → L'

(-1,2) → ( -1+2, 2-6)

(-1,2) → (1,-4)

Hence, The Coordinate of point L' is (1,-4)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3