You randomly select two cards from a standard 52-card deck. What is the probability that the first card is not a face card (a king, queen, or jack) and the second card is a face card if you replace the first card before selecting the second?

There are 3 face cards per suit, so 12 face card in total. This implies that there are 40 non-face cards in the deck. So, the probablity of picking a face card is 12/52, and the probability of picking a non-face card is 40/52.

Since we replace the first card, the two picks follow the same probability, because we're picking from a whole deck every time.

The probability of two independent events happening is the product of the two probabilities, so we have

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680