Two guy wires from the top of a 200-foot radio antenna are anchored to the ground by two large concrete posts. The antenna is perpendicular to the ground and between the two posts. If the angles of depression from the top of the antenna to each of the posts is 46o and 48o respectively, then the distance between the two posts is:

373.22 feet

Step-by-step explanation:

The attached photo contains the diagram illustrating the scenario. 2 right angle triangles ACD and BCD are formed.

The distance between the two posts is AD + BD

To determine AD, we would apply the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side

Tan 46 = 200/AD

AD = 200/Tan 46 = 200/1.0355

AD = 193.14

To determine BD, we would also apply the tangent trigonometric ratio. Therefore

Tan 48 = 200/BD

BD = 200/Tan 48 = 200/1.1106

BD = 180.08

Therefore, the distance between the two posts is

193.14 + 180.08 = 373.22 feet

answer: i cant see the picture

step-by-step explanation:

can u take a better picture

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.