Determine the dimensions of the constants A and B from the following derivative where y has the dimension of length and t has the dimension of time. (Use the following as necessary: L and T, where L is the unit of length and T is the unit of time.) dy/dt

1. A=L/T^3

2. B=L/T

Step-by-step explanation:

Assume the equation y = At^3 +Bt describes the motion of a particular object,

with y having the dimension of length and t having the dimension of time. Determine the dimensions of the constants A and B. (Use the following as necessary:

L and T, where L is the unit of length and T is the unit of time.)

could be the possible concluding part of this question

let us give equate  the right hand side with dimension L

y=At^3 +Bt

y=(At^3)

y=has the dimension of length and t has the dimension of time, recall

L=AT^3

A=L/T^3

for B

L=BT

B=L/T

i need a picure

step-by-step explanation:

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: