Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 129 disks are summarized as follows:

shock Resistance
High Low
Scratch high 71 14
Resistance low 16 28
Let A denote the event that a disk has high shock resistance, and let B denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Round your answers to two decimal places (e. g. 98.77).

Find

1. P(A)
2.P(B)
3.P(A')

1) 0.674, 2) 0.659, 3) 0.326.

Step-by-step explanation:

Since we have given that

Shock Resistance            High          Low      Total

Scratch high                       71               14           85

Resistance low                   16               28          44

Total                                   87              42           129

A be the event that a disk has high shock resistance

B be the event that a disk has high scratch resistance

1) P(A) is given by

2)  P(B) is given by

3) P(A') is given by

Hence, 1) 0.674, 2) 0.659, 3) 0.326.

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

one set of data has more variation than the other. hope this !