Question 5 Your answers to questions 3 and 4 define a range for Fx. As seen in the lecture, the range can then be transformed into the usual error notation: central value ± error. The central value was already computed in question 2. What is the error? For this question, round up your final answer to two significant figures. Do not include the ± sign in your answer. Example: If the x component of F is 200±14 N, you should enter "14".

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

step-by-step explanation:

what are the statements? and what do you mean by "216 2 1 6"?