The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between0 and 7 minutes. Find the probabilty hat a randomly selected passenger has a waiting time greater than 2.25 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes. (Simplify your answer. Round to three decimal places as needed.)

0.643 = 64.3% probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

For this problem, we have that:

Uniformily distributed between 0 and 7, so

Find the probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.

Either the waiting time is 2.25 minutes or less, or it is greater than 2.25 minutes. The sum of the probabilities of these events is decimal 1. So

In which

Finally

0.643 = 64.3% probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.

the answer is 200

step-by-step explanation:

the way the question is worded, it seems to imply the $264 interest is simple interest, not compound interest.

the simple interest for 2 years is $264; the simple interest for 1 year is $132.

$132 interest on a $600 investment means an interest rate of (132/600)*100 = 22%.

the value of $200 at 22% interest compounded annually for three years is

200%281.22%29%5e3

the amount of interest is that value, minus the original $200.

  n=   0.0000 - 0.3750 i  

  n=   0.0000 + 0.3750 i

step-by-step explanation:

one of these should be correct