1.
3
rocket in the shape of a cone is attached to a
Cylinder with the same base radius. The cone has a
slant height of 15 m. The cylinder has a base diameters
of 12 m and a height of 42 m. Find the total surface
area of the rocket
15 m
12 m

1978.2 sq m

Step-by-step explanation:

Step 1:

Surface area of a cone (leaving the base which is attached to the cylinder is pi * r * l

l = 15 m

r = 6 m (Given diameter = 12)

So, area = pi * 15* 6 = 90 pi= 282.6 m sq.

Step 2 :

Area of the given cylinder which is part of the rocket is 2*pi*r*h+pi*r*r (leaving the top part of the cylinder.  

So the required area = 2*pi* 6* 42 + pi*6*6 = pi(504+36) = 540 pi =540 * 3.14 = 1695.6 sq m

Step 3 :

The area of the rocket is the 282.6+1695.6 = 1978.2 sq m