A lot of 1000 components contains 300 that are defective. Two componentsare drawn at random and tested. Let A be the event that the first componentdrawn is defective, and let B be the event that the second component drawnis defective. Find P(B|A).

299/999

Step-by-step explanation:

Total component = 1000

Number of defective components = 300

Let A be the event that the first component drawn is defective

Let B be the event that the second component drawn is defective

P(B|A) = P(A and B) / P(A)

P(A) = 300/1000 = 3/10

P(A and B) = P(A) * P(B)

P(B) = P(A and B) / P(A)

P(B|A) = P(B)

P(B) = 299/999

P(B|A) = 299/999

the answer to the expression is 83