Mathematics, 19.02.2020 05:53 KhaliylTestman

A concrete beam may fail either by shear (S) or flexure (F). Suppose that three failed beams are randomly selected and the type of failure is determined for each one. Let X = the number of beams among the three selected that failed by shear. List each outcome in the sample space along with the associated value of X.

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Answer from: darricus

X outcome1 outcome 2 outcome 3

0 F F F

1 S F F

F S F

F F S

2 S S F

F S S

S F S

3 S S S

Step-by-step explanation:

For this case we define the random variable X as the the number of beams among the three selected that failed by shear (S).

The sample space is defined as the total possible outcomes for an event.

And we know that we have two types of beams S and F. So then the possible values for X are 0,1,2. And we can create the following table with the possible outcomes;

X outcome1 outcome 2 outcome 3

0 F F F

1 S F F

F S F

F F S

2 S S F

F S S

S F S

3 S S S

Answer from: Quest

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen

Answer from: Quest

x² + 11x + 18 < 0

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2

solution: (-9, -2)

step-by-step explanation:

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