(1 point) Find an equation of the tangent plane to the parametric surface x=5rcosθx=5rcos⁡θ, y=4rsinθy=4rsin⁡θ, z=rz=r at the point (52–√,42–√,2)(52,42,2) when r=2r=2, θ=π/4θ=π/4. z = Note: Your answer should be an expression of x and y; e. g. "3x - 4y"

Denote the given surface by the vector-valued function,

Then the normal vector to this plane is

When and , the normal vector is

and so the equation of the tangent plane is

Judging by the "note", you need to write the equation as , which is trivial:

step-by-step explanation:

honestly bro aint no one got time to answer these dumb question just do it p***y

step-by-step explanation: