give the first five terms of the sequence
an=2n2+2

The answer to your question is 3, 9, 19, 33, 51

Step-by-step explanation:

Sequence                           an = 2n² + 1

1st term                               a₁ = 2(1)² + 1 = 2(1) + 1 = 2 + 1 = 3

2nd term                              a₂ = 2(2)² + 1 = 2(2)² + 1 = 2(4) + 1 = 8 + 1 = 9

3rd term                             a₃ = 2(3)² + 1 = 2(3)² + 1 = 2(9) + 1 = 18 + 1 = 19

4rd term                              a₄ = 2(4)² + 1 = 2(4)² + 1 = 2(16) + 1 = 32 + 1 = 33

5th term                              a₅ = 2(5)² + 1 = 2(5)² + 1 = 2(25) + 1 = 50 + 1 = 51

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

(x+3)(x+7)

step-by-step explanation: