Suppose that the inside bottom of a box is painted with three colors: 1/3 of the bottom area is red, 1/6 is blue, and 1/2 is white. You toss a tiny pebble into the box without aiming and note the color on which the pebble lands. Then you toss another tiny pebble into the box without aiming and note the color on which that pebble lands. What is the probability that the first pebble lands on the color blue and the second lands on red? (Enter your probability as a fraction.)

The Probability of the pebble landing on red = 1/3

The Probability of the pebble landing on blue = 1/6

The Probability of the pebble landing on white = 1/2

Total sum of probability = 1/3 + 1/6 + 1/2 = 1

The probability that the first pebble lands on blue and second pebble lands on red is:

1/6 * 1/3

= 1/18    

Step-by-step explanation:

Red, Red = 1/3 * 1/3

Red, Blue = 1/3 * 1/6

Red, white = 1/3 * 1/2

Blue, Blue = 1/6 * 1/6

Blue, Red = 1/6 * 1/3

Blue, white = 1/6 * 1/2

White, White = 1/2 * 1/2

White, Red = 1/2 * 1/3

White, Blue = 1/2 * 1/6

he sells x mount because thats eqivilqant to the maz and then divided into quarters

step-by-step explanation:

good luck on your studies! : )

david edward.