Daniella prepares a 1 mg/ml 1 mg/ml myoglobin solution. The molecular weight of myoglobin is 17.8 kDa. 17.8 kDa. Given that the ϵ ϵ of myoglobin is 15 , 000 M − 1 cm − 1 , 15,000 M−1cm−1, calculate the absorbance of the myoglobin solution across a 1 cm 1 cm path. Calculate your answer to two decimal places.

A = 0.84

Step-by-step explanation:

The absorbance of the myoglobin solution can be calculated by using the Beer-Lambert law:

Where:

A: is the absorbance

ε: is the molar attenuation coefficient = 15,000 M⁻¹cm⁻¹

l: is the  optical path length = 1 cm

C: is the concentration = 1 mg/ml  

Since the concentration is given in mg/ml and the molar attenuation coefficient is given in M (mol/L) we need to convert the concentration in mg/ml to mol/L and for that, we need to use the molecular weight of myoglobin = 17.8 kDa = 17.8x10³ g/mol:    

Now, we can calculate the absorbance of the myoglobin:

Therefore, the absorbance of the myoglobin solution is 0.84.

I hope it helps you!  

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15