What is the value of 3 x squared plus space 4 y squared if x = 2, y = 1, and z = –3?

16

Step-by-step explanation:

Write the expression in algebraic form:

3x² + 4y²

Notice we only have variables "x" and "y".

Given these variables: x = 2, y = 1, and z = –3      

We can ignore "z" because the variable is not in the equation.

Substitute x = 2 and y = 1 in the expression. In other words, replace "x" and "y" with the numbers they give you.

3x² + 4y²

= 3(2)² + 4(1)²        

Then, simplify the expression. Remember to follow BEDMAS order (brackets, exponents, division and multiplication, addition and subtraction).

= 3(2)² + 4(1)²      Solve exponents first

= 3(4) + 4(1)         Solve multiplication

= 12 + 4               Solve addition

= 16                     Answer

The value of 3 x squared plus 4 y squared is 16, if x = 2, y = 1, and z = -3.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2