Answer choices are
A- all four sides of a rhombus are congruent
B- Diagonals of a rhombus are perpendicular
C-Diagonals of a rhombus bisect each other
D-Opposite sides of a rhombus are parallel

Option C:

Diagonals of a rhombus bisect each other is the best statement to the given equation.

Solution:

Given CAMP is a rhombus.

PQ = x + 2 and QA = 3x – 14

Given equation is x + 2 = 3x – 14.

To find which statement is true for the equation:

Option A: All four sides of a rhombus are congruent.

This means CA = AM = MP = PC.

It is not relevant to the given equation.

Option B: Diagonals of a rhombus are perpendicular.

This means the angle formed in the intersection of the diagonals are 90°.

It is not relevant to the given equation.

Option C: Diagonals of a rhombus bisect each other.

This means PQ = QA and CQ = QM

This is the best statement explains why the equation is x + 2 = 3x – 14.

x + 2 = 3x – 14

2x = 16

x = 8

Option D: Opposite sides of a rhombus are parallel.

This means PM = CA.

It is not relevant to the given equation.

Hence Option C, diagonals of a rhombus bisect each other is the best statement to the given equation.

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )