A 0.45-mm-wide slit is illuminated by light of wavelength 590 nm. What is the width (in mm) of the central maximum on a screen 1.5 m behind the slit?

And if we convert this into mm we got:

Step-by-step explanation:

For this case we have the following info givenL

represent the wavelength

represent the width of the single slit

represent the longitude

And we want to find the maximum width of the central maximum in mm, so we can use the following formula:

And if we solve for w the width we got:

And replacing we got:

And if we convert this into mm we got:

a framing bias

step-by-step explanation:

rodrigo is subject to a framing bias i believe.

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.