Urn A has 3 white and 8 red balls. Urn B has 10 white and 14 red balls. We flip a fair coin. If the outcome is heads, then a ball from urn A is selected, whereas if the outcome is tails, then a ball from urn B is selected. Suppose that a white ball is selected. What is the probability that the coin landed heads?

The probability that the coin landed heads given that a white ball is selected is 0.3957.

Step-by-step explanation:

Let W = a white ball is selected.

Balls in Urn A = 3 white and 8 red = 11 balls.

Balls in Urn B = 10 white and 14 red = 24 balls.

A coin is tossed to select an urn.

If the coin turns up Heads urn A is selected and if it turns up Tails urn B is selected.

P (A) = P(B) = 0.50

Compute the probability that a white ball is selected as follows:

P (W) = P (W ∩ A) + P(W ∩ B)

        = P (White from A)×P (A) + P (White from B)×P (B)

The probability of selecting a white ball is P (W) = 0.3447.

If the coin lands Heads it implies that urn A was selected.

Then compute the probability that urn A is selected given that a white ball was selected as follows:

Thus, the probability that the coin landed heads given that a white ball is selected is 0.3957.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

6 cm

step-by-step explanation: