"What is the rate of growth of 20 bacterial if after 4 hours there are 3000" Fill in each step to solve the problem: Using the formula A\:=\:A_oe^{kt}A = A o e k t, let A = , A_oA o = and t = Start by dividing each side by in order to isolate the base Next, rewrite as a logarithm, which turns into Finally, solve for k to get the rate of

1.00213

Step-by-step explanation:

Using the formula provided for the growth

A (t) = A0e^kt where A (t) is the population after time t, A0 is the initial population k is growth constant and t is time

substitute the values given into  the formula

3000 =  20 e^5k

divide both side by 20

3000 /20 = e^5k

150 = e^5k

take natural logarithm of both side

In 150 = 5k

k = In 150 / 5 = 1.00213

d

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