The math department of a college has 20 faculty members, of whom 5 are women and 15 are men. A curriculum committee of 4 faculty members is to be selected. A. How many ways are there to select the committee that has more women than men?B. How many ways are there to select a committee?
C. If the positions in the committee are titled chair, vice chair, and secretary, in how many ways can this committee be formed among the 24 AMS faculty members?

a) Therefore, exists 155 ways.

b) Therefore, exists 4845 ways.

c) That is not possible.

Step-by-step explanation:

We know that the math department of a college has 20 faculty members, of whom 5 are women and 15 are men. A curriculum committee of 4 faculty members is to be selected.

a) We calculate how many ways are there to select the committee that has more women than men

Therefore, exists 155 ways.

b) We get:

Therefore, exists 4845 ways.

c) That is not possible.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer