Find the unit tangent vector, the principal normal vector, and an equation in x, y,z for the osculating plane at the point on the curve corresponding to the indicated value of t. rtí) = (3cos(2t))i +(3sin(2t))j+2tk t=1/4Pi (T=3/10root10i+1/10root10k, N=j, plane(x+1+3z-3Pi)=0) (T=3/10root10i+1/10root10k, N=-j, plane(x+3z-3/2Pi)=0) (T=3/10root10i+1/10root10k, N=-j, plane(2x+2-3z+3/2Pi)=0) (T=3/10root10i+1/10root10k, N=j, plane(-x+3z-6)=0)

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so:

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

well your weight will go up if you are not going to burn the calories/ carbs

step-by-step explanation:

it would be 0.18 because when the other choices are converted they equal those two numbers.   hope this !