The number of traffic accidents per day on a certain section of highway is thought to be Poisson distributed with a mean equal 2.19. Then the probability of no accidents on this section of highway during one day period is approximately: a. 0.457 b. 0.112 c. 0.296 d. 0.211 e. 0.318

option B is the correct answer

Step-by-step explanation:

The formula for poisson distribution is expressed as

P(x = r) = (e^- µ × µ^r)/r!

Where

µ represents the mean of the theoretical distribution.

r represents the number of successes of the event.

From the information given,

µ = 2.19

For the probability of no accidents on this section of highway during one day period, r = 0

Therefore,

P(x = 0) = (e^- 2.19 × 2.19^0)/0!

P(x = 0) = (e^- 2.19 × 1)/1

P(x = 0) = 0.112

idk

step-by-step explanation: