Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and A2 the event that the right leg tag is lost. Suppose these two events are independent and P(A1)=P(A2)=.4. Find the probability that exactly one tag is lost, given that at least one tag is lost.

0.51

Step-by-step explanation:

Since A1 and A2 are independent so

P(A1 and A2) = P(A1)P(A2) = 0.3*0.3 = 0.09

By the addition rule, the probability that at least one leg tag is lost is

P(A1 or A2) = P(A1) + P(A2) - P(A1 and A2) = 0.3+0.3-0.09 = 0.51

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

answer: 270

step-by-step explanation:

you have to times 200 by 1.35 to get your answer