A waitress sold 16 ribeye steak dinners and 26 grilled salmondinners, totaling $596.12 on a particular day. Another day she sold 28 ribeye steak dinners and 13 grilled salmon dinners, totaling $584.01 . How much did each type of dinner cost? (Round to the nearest hundredth as needed.)

A. What is the cost of ribeye steak dinners?
B. what is the cost of salmon dinners?

(A) $14.30

(B) $14.13

Step-by-step explanation:

Let x represent cost of each ribeye steak dinner and y represent cost of each grilled salmon dinner.

(B) We have been given that a waitress sold 16 ribeye steak dinners and 26 grilled salmondinners, totaling $596.12 on a particular day. We can represent this information in an equation as:

We are also told that another day she sold 28 ribeye steak dinners and 13 grilled salmon dinners, totaling $584.01. We can represent this information in an equation as:

Now, we will use substitution method to solve our system of linear equations. From equation (1), we will get:

Upon substituting this value in equation (2), we will get:

Therefore, cost of each grilled salmon dinner is $14.13.

(A) To find the cost of each ribeye dinner, we will substitute in equation .

Therefore, the cost of ribeye steak dinners is $14.30.

452,489 to the nearest thousand is 452,000