A certain type of storage battery lasts, on average 3.0 years with a standard deviation of 0.5 year. Assuming that battery life is normally distributed, answer the following question. a. What is the probability that a randomly selected above types of battery will last less than 2.3 years

Step-by-step explanation:

Assuming that the battery life is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = battery life in years

µ = mean

σ = standard deviation

From the information given,

µ = 3

σ = 0.5

We want to find the probability that a randomly selected above types of battery will last less than 2.3 years. It is expressed as

P(x < 2.3)

For x = 2.3

z = (2.3 - 0.3)/0.5 = - 1.4

Looking at the normal distribution table, the probability corresponding to the z score is 0.08076

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870