. A survey found that women spend on average $146 on beauty products during the summer months. Assume the standard deviation is $28. Find the percentage of women who spend less than $160.00. Assume the variable is normally distributed.

69.2%

Step-by-step explanation:

Assuming that the amount that women spend on beauty products during the summer months is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = amount spent.

µ = mean

σ = standard deviation

From the information given,

µ = $146

σ = $28

The probability of women who spend less than $160.00 is expressed as

P(x < 41)

For x = 160

z = (160 - 146)/28= 0.5

Looking at the normal distribution table, the probability corresponding to the z score is 0.6915

Therefore, the percentage of women who spend less than $160.00 is

0.6915 × 100 = 69.2%

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%

the formula of a midpoint between a abd b: