Solve this quadratic equation by completing the square x^2-4x-13=0

x = 2 ±

Step-by-step explanation:

Given

x² - 4x - 13 = 0 ( add 13 to both sides )

x² - 4x = 13

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 2)x + 4 = 13 + 4

(x - 2)² = 17 ( take the square root of both sides )

x - 2 = ± ( add 2 to both sides )

x = 2 ± ← exact solutions

answer: 1 + 1 = 11

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: