A rectangular park is 50 meters wide and 80 meters long.
Give the length and width of another rectangular park that has the same perimeter but a smaller area.

Length = 90m

Width = 40m

Step-by-step explanation:

Width of rectangle A = 50m

Length of rectangle A = 80m

Perimeter of rectangle A = 2 * (L+W) = 2 * (50+80) = 260m

Area of rectangle A = L * W = 50 * 80 = 4000m²

Perimeter of rectangle A = Perimeter of rectangle B = 260m

Length of rectangle B = 90m

width of rectangle B = 40m

Perimeter of rectangle B = 2 * (L+W) = 2 * (40+90) = 260m

Area of rectangle B = L * W = 40 * 90 = 3600m²

i can try and you the very best that i can.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2