In the interval 0 degrees Find the value for x in which sin=0.6691
To the nearest degree

42° and 138°.

Step-by-step explanation:

Here we use the identity that

.

Now, to find , we make use of the inverse sine function:

Another solution to this is

Thus, the values of in the interval for which are 42° and 138°.

-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363