During the first month, the company received 4,264 phone calls. during the second month, the company received 25% more phone calls than in the first month. during the third month, the company received 6,396 phone calls. What was the percent increase in the number of phone calls from the second month to the third month?

20%

Step-by-step explanation:

We have been given that during the the first month, the company received 4,264 phone calls. During the second month, the company received 25% more phone calls than in the first month.

Let us find number of calls received during 2nd month by multiplying 4,264 by 1.25 as .

Now, we will use percent increase formula as shown below:

Therefore, there was a 20% increase in the number of phone calls from the second month to the third month.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

answer: sine

step-by-step explanation: