If 60 lbs of force must be applied to the valve for it to open, how much upward force must push rod X apply for the valve to open?

It must push 40 lbs of force to open the valve.

Step-by-step explanation:

The momentum at one end of the pivot must be equal to the momentum at the other end. Assuming the 60 lbs of force (F1) is applied at 2 inches from the pivot (d1) and the upward force (F2) is applied at 3 inches from the pivot (d2), then:

F1*d1 = F2*d2

Solving for F2 we get:

F2 = F1*d1/d2

F2 = 60*2/3 = 40 lbs of force

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mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: