Let f(x) = x^2-4
What is the average rate of change of f(x) from -5 to -2 ?
A. -7
B. -1/7
C. 7
D. 1/7

A. -7.

Step-by-step explanation:

f(-5) = (-5)^2 - 4 = 21.

f(-2) = (-2)^2 - 4 = 0.

Average rate of change =[ f(-2) - f(-5)] / ( -2 - (-5))

= (0 - 21) / 3

=  -7.

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.