A Car traveling at 16 m/s starts to decelerate steadily. It comes to a complete stop in 8 seconds, what is its acceleration?

VI Initial velocity: 16 m/s

VF Final velocity: 0 m/s

t: 8s  

Acceleration/A is unknown

vf = Vi+a*t  

0 = 16 + a * 8

0-16 = 16-16 + a * 8

-16= a 8 or 8a = -16

8a/8 = -16/8

=-2 m/s

The acceleration is -2m/s (decelerates)

The acceleration is -2m/s (decelerates)

Step-by-step explanation:

VI Initial velocity: 16 m/s

VF Final velocity: 0 m/s

t: 8s  

Acceleration/A is unknown

vf = Vi+a*t  

0 = 16 + a * 8

0-16 = 16-16 + a * 8

-16= a 8 or 8a = -16

8a/8 = -16/8

=-2 m/s

The acceleration is -2m/s (decelerates)

since both sides equal, there are infinitely many olutions.

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic