3-12. If P(X A) 0.3, P(X B) 0.25, P(X C) 0.60, P(X A B) 0.55, and P(X B C) 0.70, determine the following probabilities. (a) P(X A) (b) P(X B) (c) P(X C) (d) Are A and B mutually exclusive

a) P(A')=0.7.

b) P(B')=0.75.

c) P(C')=0.4.

d) d) Therefore, we conclude that are A and B mutually exclusive events.

Step-by-step explanation:

From task we know that are:

P(A)=0.3

P(B)=0.25

P(C)=0.6

Therefore, we get calculate the next probabilities:

a) P(A')=1-P(A)

P(A')=1-0.3

P(A')=0.7.

b)  P(B')=1-P(B)

P(B')=1-0.25

P(B')=0.75.

c) P(C')=1-P(C)

P(C')=1-0.6

P(C')=0.4.

d) Therefore, we conclude that are A and B mutually exclusive events.

i'm not sure what you mean but in todays world there is a lot of women that are the bread winners in the family. there is a lot more single mothers now that are going back to get an education which is boosting the economy. i believe there has been a boost in the economy due to women the cosmetic industry is boosting, chemist, the sky is becoming the limit for women in todays economy. most women are also putting off having kids just to make sure they have a education. i don't know how these two relate though to scriptures because it's not the way the lord wanted it. the man is suppose to be the bread winner and due to social media and the easy access we have there is a lot of cheating going on.

step-by-step explanation:

c is the answer

step-by-step explanation: