Approximately 80,000 marriages took place in the state of New York last year. Estimate the probabilitythat for at least one of these couples, (a) both partners were born on April 30; (b) both partners celebrated their birthday on the same day of the year. State your assumptions.

Step-by-step explanation:

Given that there are 80000 marriages in Newyork last year

i.e. 80000 pairs were there

Each partner is independent of the other to have birthday.

Last year being 2019 was not a leap year so had 365 days

For any one to have Apr 30 as birth day = 1/365 (as all days are equally likely)

For couples together having same birth day would be

Out of 80000 each couple is independent of the other

X no of couples having birthday on Apr 30 is binomial with p = 1/365^2

Since n is very large we approximate to normal with

mean= 0.6005, and variance = np(1-p) = 0.6005

Std dev = 0.7749

a) Prob atleast one set of partners have Apr 30 as birthday

= P(X≥0)

= P(x≥-0.05) (with continuity correction)

= 1-0.2006

=0.7994

b) both partners celebrated their birthday on the same day of the year.

Here p will change to

q= 0.99726

P(X

X is normal with mean = 219.87 and std dev = 14.78

P(X>=-0.05) after continuity correction

=1

Almost certain event.

hit or miss i guess they never miss huh

step-by-step explanation:

you got a boyfriend i bet he doesnt kiss ya

i can not answer the question due to the fact that you spelled "carton" as "cartoon", a cartoon is something you watch on tv, a carton is a box that holds things. and also you've been waiting for this question for a while so why don't you get off your lazy a** and try to figure it out for yourself for once!

step-by-step explanation:

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look above, and leave your comments down below, and don't for get a five stars and a and brainliest xd

sorry for the stars in the middle of words its because it wouldn't let me submit. xd