Organizers of an Internet training session will charge participants $150 to attend. It costs $3000 to reserve the room, hire the instructor, bring in the equipment, and advertise. Assume it costs $25 per student for the organizers to provide the course materials.

a. How many students would have to attend for the company to break even?

b. If the trainers think, realistically, that 20 people will attend, then what price should be charged per person for the organization to break even?

Step-by-step explanation:

given that organizers of an Internet training session will charge participants $150 to attend. It costs $3000 to reserve the room, hire the instructor, bring in the equipment, and advertise. Assume it costs $25 per student for the organizers to provide the course materials.

Let us assume x students join.

Then we get revenue = 150 x

costs= fixed costs such as reservation charges, hiring instructor+ variable cost per student

Total cost=3000 +25x

To break even

a) Cost = revenue

24 students should be enrolled to break even.

b) If 20 people will attend revenue would be

20(u) where u = charge per participant.

cost = 3000+25(20) = 3500

To break even 20u =3500

Or u = 175

So if 20 people attend 175 dollar per participant should be charged to break even.

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website: