How many solutions does the following system of equations have?
2y=2x+4
y=3.x + 2

it has no solutions

Step-by-step explanation:

The given system of equations is expressed as

2y = 2x + 4 - - - - - - - - - - 1

y = 3x + 2 - - - - - - - - - - - - 2

We would apply the substitution method by substituting equation 1 into equation 2. It becomes

2(3x + 2) = 2x + 4

6x + 4 = 2x + 4

Subtracting 2x and 4 from the left hand side and the right hand side of the equation, it becomes

6x - 2x + 4 - 4 = 2x - 2x + 4 - 4

4x = 0

Therefore, the system of equations have no solutions.

idk lol xd

step-by-step explanation:

ez do it yourself lazy

so, converting firstly the mixed fractions to improper fractions and then "adding".