If 25 servings of guacamole have been sold from a batch, in ounces, what is the standard deviation of how much is left? (Suppose the servings of guacamole are independent.)

The standard deviation of the the left guacamole is 12.51.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

From the data

Population mean==2.2 ounces

Population Standard Deviation==0.4 ounces

Batch mean==80 ounces

Batch Standard Deviation==7 ounces

As per serving is 2.2 ounces

So for 25 servings, Guacamole used is

25*2.2=55 ounces

Thus the Guacamole left is given as

Batch-55=80-55-25 ounces

As it is given that the servings are independent, thus

Var(Z)=Var(X)+Var(Y)

Here Var(Z) is the variance of the Batch, X is the served guacamole and Y is the left guacamole

Also as variance is given as so putting the values

So the standard deviation of the the left guacamole is 12.51.

step-by-step explanation:

f(x)=2x^2 -1 

translation is a function transformation that transform the function in a way of translating. by translating the function its graph is moved  up an down. moving the function f(x) 2 units to the left will be the new function g(x) with the equation: g(x)=f(x+2)=2(x+2)^2 -1

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: