The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initial condition y(−2) = 4.

1. y = 4 p 1 + 16(x2 − 4)
2. y = 1 p 1 + 64(x 2 − 4)
3. y = 4 p 1 + 4(x2 − 4)
4. y = 4 p 1 + 64(x 2 − 4)
5. y = 1 p −4(x2 − 4) + 1

The correct option is 4

Step-by-step explanation:

The solution is given as

Now for the initial condition the value of C is calculated as

So the solution is given as

Simplifying the equation as

So the correct option is 4

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step-by-step explanation:

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