In part D, we concluded that the Pythagorean triple (5,12,13) can't be generated from the identity
(x2 - 1)2 + (2x)2 = (x2 + 1)2, which has only one variable, because the length of the hypotenuse (13 units)
and the length of the longer of the other two legs (12 units) are not 2 units apart. This illustrates the
triangle from the original triple:
2x
Find a two-variable identity by incorporating a second variable, y, into the single-variable identity. Note
that x > 1, x > y, and x andy are positive integers.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4