Set up a linear system and solve.
The sum of two positive integers is 35. When the smaller integer is subtracted from twice the
larger, the result is 34. Find the two integers.

The smaller integer is 12, while larger integer is 23

Step-by-step explanation:

The sum of two positive integer;

a + b = 35, when smaller integer is subtracted from twice the larger integer we have, 2a - b = 34 assuming b as the smaller integer, so your equation goes this way.

a + b = 35(1)

2a - b = 34(2). To solve by elimination method add both equation. We have;

3a + 0 = 69

3a = 69, divide both sides by 3.

3a/3 = 69/3 so we have;

a = 23

To know the value of b, substitute 23 for the value of a in any of the equations, let's go with (1). From one we have;

a + b = 35 if a = 23 we have;

23 + b = 35

b = 35 - 23

b = 12.

Check: a + b = 35

23 + 12 = 35

35 = 35

The answer is correct.

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11-1 > 1-1+a

-12 > a